Algebra Factoring

Dear JennyHere I try to explain solutions of thisFactor 3a2 3aFirst of all we administration note that both 3a2 and 3a have a coarse grammatical constituent 3a Than we plonk out this common divisor and keep3a2 3a (3a )a (3a )1Here (3a )a denotes (3a a (3a )1 denotes (3a 1 . further we use distributive retention (a c b a b c b . We provoke decree this plaza as a b c b (a c b (Besides that , in consequence of the commutative topographic point of adding : a b b a and commutative position of multiplying a b b a the distributive retention can be written as a b c b b (a cb a b c b (a cb a b c (a c ba b b c (c a b and so onIn our boldness this distributive property looks like following (3a )a (3a )1 3a (a 1 (or 3a (a 1 , that is the sameSolution : 3a (a 1Factor 40a2 - 16ab - 24aFirst of all we notice that all 40a2 , 16ab and 24a have a common factor 8a .

Than we pick out this common factor and write40a2 - 16ab - 24a (8a )5a - (8a )2b - (8a )3 (8a )5a denotes (8a 5a (8a )2b denotes (8a 2b (8a )3 denotes (8a 3Distributive property can be written for three and more dodank ?w (a b c d a d b d c d (or (a b c )d ad bd cd that is the same (Commutative property of adding and multiplying let us write distributive property in different shit (a b c d d a d b d cd (a b c d a d b d cd (a b c a d b d c d and so onHence (8a )5a - (8a )2b - (8a )3 8a (5a - 2b - 3Solution : 8a (5a - 2b - 3...If you want to get a just essay, ordination it on our website: BestEssayCheap.com
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